题解 | #计算日期到天数转换#

#include <iostream>
#include <vector>
using namespace std;

//万年历
int main() {
    int year, month,day;
    vector<int> month_days(12);
    month_days={31,28,31,30,31,30,31,31,30,31,30,31};
    while (cin >> year >> month >> day) { // 注意 while 处理多个 case
        //首先根据年来确定二月天数 闰年
        if(year % 400 && (year % 4==0 && year % 100!=0)){
            month_days[1] = 29;
        }else{
            month_days[1] = 28;
        }
        int sum = 0;
        for(int i=0;i<month-1;i++){
            sum += month_days[i];
        }
            sum += day;
            cout<<sum<<endl;
    }
    return 0;

}
// 64 位输出请用 printf("%lld")