题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <iostream> using namespace std; int main() { long seconds; cin >> seconds; int h, m, s; // 除 求模运算 h = seconds / (60 * 60); m = (seconds % (60 * 60)) / 60; s = seconds % 60; cout << h << " " << m << " " << s << endl; return 0; }