题解 | #牛牛的西格玛#
牛牛的西格玛
https://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include <stdio.h>
int sum(int n)
{
if(n>1)
return sum(n-1)+n;
else
return 1;
}
int main()
{
int n;
scanf("%d",&n);
printf("%d",sum(n));
return 0;
}
