题解 | #牛牛的快递#
牛牛的快递
https://www.nowcoder.com/practice/41b42e7b3c3547e3acf8e90c41d98270
#include <stdio.h>
int main() {
float a;
int pri;
char b;
int count = 0;
scanf("%f %c",&a,&b);
if(a<=1)
{
pri = 20;
}
else
{
for(float i=a-1;i>0;i--)
{
count++;
}
pri = 20 + count;
}
switch (b)
{
case 'y':pri = pri + 5;break;
case 'n':break;
}
printf("%d",pri);
return 0;
}
