题解 | #牛牛的字符矩形#
牛牛的字符矩形
https://www.nowcoder.com/practice/2dbf0151eb71402e968a2a8e59092568
#include <stdio.h>
int main()
{
char x[2][2];
char ch;
int k=1;
ch=getchar();
int i,j;
for(i=0;i<=2;i++)
{
for(j=0;j<=2;j++)
{
x[i][j]=ch;
printf("%c",x[i][j]);
if(k%3==0)
printf("\n");
k++;
}
}
return 0;
}
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