题解 | #有序序列合并#
有序序列合并
https://www.nowcoder.com/practice/a9e943b0dab142759807d0cfb6863897
#include<stdio.h>
int main()
{
int i=0;
int j=0;
int m=0;
int n=0;
int arr1[1000] = { 0 };
int arr2[1000] = { 0 };
scanf("%d %d", &n, &m);
for (i = 0;i < n;i++)
{
scanf("%d", &arr1[i]);
}
for (j = 0;j < m;j++)
{
scanf("%d", &arr2[j]);
}
i=0;//遍历一遍数组
j=0;
while (i < n && j < m)
{
if (arr1[i] < arr2[j])
{
printf("%d ", arr1[i]);
i++;
}
else
{
printf("%d ", arr2[j]);
j++;
}
}
//若跳出循环进入则下面循环
while (i < n)
{
printf("%d ", arr1[i]);
i++;
}
while (j < m)
{
printf("%d ", arr2[j]);
j++;
}
return 0;
}
