题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
a = input()
count_s = {}
# 统计
for a1 in a:
if a1 in count_s:
count_s[a1] += 1
else:
count_s[a1] = 1
# 得到次数最小的值
min_val = sorted(count_s.items(), key=lambda x: x[1])[0][1]
# 得到要删除的字母
removed_alphas= []
for k, v in count_s.items():
if v == min_val:
removed_alphas.append(k)
# 删除这些字母后的字符串
for ra in removed_alphas:
a = a.replace(ra, '')
print(a)
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