题解 | #牛牛学数列#
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int n,s=0,t=1,i;
scanf("%d",&n);
for(i=1;i<=n;n++)
{
if(n%2==0)
s=-n/2;//1-2+3-4=-2
else
s=(n+1)/2;
break;
}
printf("%d\n",s);
return 0;
}
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