题解 | #在字符串中找出连续最长的数字串#

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
    public static void main(String[] args){
        Scanner in = new Scanner(System.in);

        while(in.hasNext()){
            solution1(in);
            // solution2(in);
        }
    }


    /**
     * 动态规划: dp[i]表示当前局部数字子串长度
     * @param in
     */
    private static void solution1(Scanner in){
        String input = in.nextLine();

        int len = input.length();
        int[] dp = new int[len+1];

        int max = 0;
        for(int i=1; i<=len; i++){
            char ch = input.charAt(i-1);
            if(Character.isDigit(ch)){
                dp[i] = dp[i-1] + 1;
                if(max < dp[i]){
                    max = dp[i];
                }
            }
        }

        for(int i=1; i<=len; i++){
            if(dp[i] == max){
                System.out.print(input.substring(i-max, i));
            }
        }

        System.out.println(","+max);
    }


    /**
     * 正则
     * @param in
     */
    private static void solution2(Scanner in){
        String input = in.nextLine();

        String[] digitParts = input.split("[^0-9]+");
        ArrayList<String> list = new ArrayList<>();
        int max = 0;

        for(String part: digitParts){
            if(max < part.length()){
                max = part.length();
                list.clear();
                list.add(part);
            }else if(max == part.length()){
                list.add(part);
            }
        }

        StringBuilder sb = new StringBuilder();
        for(String maxPart: list){
            sb.append(maxPart);
        }
        sb.append(","+max);

        System.out.println(sb);
    }
}