题解 | #将真分数分解为埃及分数#

简单模拟，大力出奇迹

#include <cstdlib>
#include <iostream>
#include <sstream>
#include <string>
#include <bits/stdc++.h>
using namespace std;

long long gcd(long long a, long long b){
    return b? gcd(b, a%b) : a;
}

int main() {
    string a, b, s;
    while (getline(cin, s)) {
        stringstream ss;
        ss.str(s);
        getline(ss, a, '/');
        getline(ss, b);
        long long n1 = atoi(a.c_str());
        long long n2 = atoi(b.c_str());
        long long g = gcd(n1, n2);
        if(g!=1){
            n1 /= g;
            n2 /= g;
        }
        double num = 1.0* n1 / n2;
        vector<long long> nums;
        for(int i=2;true;i++){
            if(n1==1) {
                nums.push_back(n2);
                break;
            }
            long long g = gcd(i, n2);
            if(n1 * i / g >= n2 /g){
                n1 = n1 * i / g - n2 / g; 
                n2 = n2 * i / g ;
                g = gcd(n1, n2);
                n1 /=g;
                n2 /=g;
                nums.push_back(i);
            }
        }
        for(int i=0;i<nums.size();i++){
            cout << "1/" << nums[i];
            if(i!=nums.size()-1) cout << "+";
        }
        cout << endl;
    }

}
// 64 位输出请用 printf("%lld")