题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main()
{
int i = 2;
int n = 0;
scanf("%d",&n);
int x = (i << (n - 1));
printf("%d", x);
return 0;
}
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main()
{
int i = 2;
int n = 0;
scanf("%d",&n);
int x = (i << (n - 1));
printf("%d", x);
return 0;
}
相关推荐