题解 | #时间转换#

#include <stdio.h>
 int main()
{
	int s = 0;
	int h = 0;
	int m = 0;
	scanf("%d", &s);
	if (s < 60)
		printf("%d %d %d",0,0, s);
	else if (s >= 60 && s < 3600)
	{
        printf("%d ",0);
		m = s / 60;
		printf("%d ", m);
		s = s%60;
		printf("%d ",s);
	}
	else
	{
		h = s / 3600;
		printf("%d ", h);
		m = s % 3600 / 60;
		printf("%d ", m);
		s = s % 3600 % 60;
		printf("%d ", s);
	}
	return 0;
}