题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
#include <math.h>
int main()
{
int n = 0;
int h = 0;
int m = 0;
int a = 0;
while(scanf("%d %d %d", &n, &h, &m) != EOF)
{
if (m <= n * h)
{
a = n - m /ceil( h * 1.0);//ceil向上取整函数
}
}
printf("%d", a);
return 0;
}
