题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int a;
scanf("%d",&a);
int i=1;
int t;
while (i<=a){
t=2*t;
i++;
continue;
}
printf("%d",t);
return 0;
}
