题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h> int main() { int n,h,m; scanf("%d %d %d", &n, &h,&m); if(m%h==0) { n=n-(m/h); if(n<0) { n=0; } } else if(m%h<h) { n=n-(m/h)-1; if(n<0) { n=0; } } printf("%d", n); return 0; }