题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main() {
int n,h,m;
scanf("%d %d %d", &n, &h,&m);
if(m%h==0)
{
n=n-(m/h);
if(n<0)
{
n=0;
}
}
else if(m%h<h)
{
n=n-(m/h)-1;
if(n<0)
{
n=0;
}
}
printf("%d", n);
return 0;
}
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