题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int seconds;
int hour;
int min;
scanf("%d", &seconds);
hour=seconds/3600;
min=(seconds-(hour*3600))/60;
seconds=seconds-(hour*3600)-min*60;
printf("%d %d %d",hour,min,seconds);
return 0;
}
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