题解 | #小乐乐改数字#

#include <stdio.h>
#include<math.h>
int main() {
    long long n, a;
    static long long b=0;
    int arr[9] = {0};
    scanf("%lld", &n);
    for (int i = 0; i < 9; i++) {
        a = n % 10;
        if (a % 2 == 0) {
            arr[i] = 0;
        } else {
            arr[i] = 1;
        }
        n = n / 10;
        b += arr[i] * pow(10.0, i);
    }
    printf("%lld", b);
    return 0;
}