题解 | #牛牛的二三七整除#
牛牛的二三七整除
https://www.nowcoder.com/practice/b2cf0b791245436f8f0591ae9f4c664f
#include <stdio.h>
int main()
{
int l = 0;
int a = 0;
int i = 0;
int arr[3] = { 2,3,7 };
scanf("%d", &a);
for (i = 0; i < 3; i++)
{
if (a % arr[i] == 0)
{
printf("%d ",arr[i]);
continue;
}
else
{
l++;
continue;
}
}
if (l == 3)
{
printf("n");
}
return 0;
}
简单应用了一下数组。但感觉还是有些繁琐
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