SQL22题解 |#统计每个学校的答过题的用户的平均答题数#
统计每个学校的答过题的用户的平均答题数
https://www.nowcoder.com/practice/88aa923a9a674253b861a8fa56bac8e5
SELECT university,
count(question_id)/count(distinct Q.device_id) AS avg_answer_cnt
FROM question_practice_detail AS Q
INNER JOIN user_profile AS U
ON Q.device_id = U.device_id
GROUP BY university;
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