题解 | #字符串加密#
字符串加密
https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3
key = input().strip()
target = input().strip()
alphabet = [chr(x) for x in range(97, 123)]
keyalphabet = []
result = ''
for k in key:
if k not in keyalphabet:
keyalphabet.append(k)
for s in alphabet:
if s not in keyalphabet:
keyalphabet.append(s)
for t in target:
result += keyalphabet[alphabet.index(t)]
print(result)
投递新浪&微博等公司10个岗位
