题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型vector * @param target int整型 * @return int整型 */ int search(vector<int>& nums, int target) { int left = 0; int right = nums.size() - 1; int mid; if (nums.empty()) { return -1; } else if (target < nums.front() || target > nums.back()) { return -1; } while (left <= right) { mid = left + (right - left) / 2; if (nums.at(mid) == target) { return mid; } else if (nums.at(mid) < target) { left = mid + 1; } else { right = mid - 1; } } return -1; } };