题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include<iostream>
int main()
{
long int seconds;
std::cin >> seconds;
std::cout << seconds / 3600 <<" "<< (seconds % 3600) / 60 << " " << (seconds % 3660) % 60;
return 0;
}
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