题解 | #统计字符串中子串出现的次数#

#include <iostream>
#include <cstring>
using namespace std;

int main() {

    char str[100] = { 0 };
    char substr[100] = { 0 };

    cin.getline(str, sizeof(str));
    cin.getline(substr, sizeof(substr));

    int count = 0;

    // write your code here....
    int j;
    for(int i = 0;str[i]!='\0';++i)
    {
        for( j = 0;substr[j]!='\0';++j)
        {
            if(str[i+j] == substr[j])//‘i+j’表示将str第i个字符当做首字符与substr相比较
            {
                continue;
            }
            else
            {
                break;
            }
        }
        if(substr[j]=='\0')
        {
            ++count;
        }
    }
    cout << count << endl;
    
}