题解 | #翻转牛群结构#
翻转牛群结构
https://www.nowcoder.com/practice/f17e1aa5329f492f9107cbe303222ad6
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return TreeNode类
*/
public TreeNode invertTree (TreeNode root) {
// write code here
if (root == null) return root;
TreeNode left = root.left;
TreeNode right = root.right;
root.left = invertTree(right);
root.right = invertTree(left);
return root;
}
}
- 边界值:root等于null,直接返回
- 分别递归左右子树进行翻转
线性表基础 文章被收录于专栏
链表、递归、栈
