题解 | #数组元素反转#

#include <iostream>
using namespace std;

int main() {

    int arr[6] = { 0 };

    int len = sizeof(arr) / sizeof(int);
    
    for (int i = 0; i < len; i++) {
        cin >> arr[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }
    int b[6];
    int j=0;
    // write your code here......
    for(int i=len-1;i>=0;i--)
    {
        b[j] = arr[i];
        j++;
    }
    for(int i=0;i<len;i++)
    {
        arr[i] = b[i];
    }

    cout << "[";
    for (int i = 0; i < len; i++) {
        if (i == len - 1) {
            cout << arr[i] << "]" << endl;
            break;
        }
        cout << arr[i] << ", ";
    }

    return 0;
}