题解 二 O(1)空间复杂度 | #跳台阶#
跳台阶
https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param number int整型 * @return int整型 */ int jumpFloor(int number) { // write code here vector<int> dp(number+1, 0); int r = 1; int l = 1; int cur = 1; for(int i = 2;i<=number;i++){ cur = l + r; l = r; r = cur; } return cur; } };