题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ public ListNode reverseBetween (ListNode head, int m, int n) { // write code here if(m == n) return head; if(m == 1){ ListNode L1 = head; int mc = m; int nc = n; while(nc != 1){ nc--; L1 = L1.next; } ListNode L2 = L1; ListNode L3 = L2.next; L1 = head; L2.next = null; ListNode pre = L3; ListNode cur = L1; while(cur != null){ ListNode temp = cur.next; cur.next = pre; pre = cur; cur = temp; } return pre; } else{ ListNode L1 = head; ListNode L2 = head; ListNode L3 = head; ListNode L4 = head; int mc = m; int nc = n; while(mc != 1){ mc--; L2 = L2.next; if(L2 != L1.next){ L1 = L1.next; } } while(nc != 1){ nc--; L3 = L3.next; } L4 = L3.next; L3.next = null; L1.next = L3; ListNode pre = L4; ListNode cur = L2; while(cur != null){ ListNode temp = cur.next; cur.next = pre; pre = cur; cur = temp; } return head; } } }
菜鸟第一次晒屎山代码。还是用了反转列表的思路,但是分了两种情况:
1.从第一个开始转
2.不是从第一个开始转