题解 | #对称的二叉树#
对称的二叉树
https://www.nowcoder.com/practice/ff05d44dfdb04e1d83bdbdab320efbcb
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param pRoot TreeNode类
* @return bool布尔型
*/
public boolean isSymmetrical (TreeNode pRoot) {
if (pRoot == null) {
return true;
}
if (pRoot.left == null && pRoot.right != null ||
pRoot.left != null && pRoot.right == null) {
return false;
}
if (pRoot.left == null && pRoot.right == null) {
return true;
}
if (pRoot.left.val != pRoot.right.val) {
return false;
}
List<Integer> left = new ArrayList<>();
List<Integer> right = new ArrayList<>();
addLeft(pRoot.left, left);
addRight(pRoot.right, right);
if (left.size() != right.size()) {
return false;
}
for (int i = 0; i < left.size(); i ++) {
if (left.get(i) != right.get(i)) {
return false;
}
}
return true;
}
public void addLeft(TreeNode root, List<Integer> list) {
if (root == null) {
list.add(null);
return;
}
list.add(root.val);
addLeft(root.left, list);
addLeft(root.right, list);
}
public void addRight(TreeNode root, List<Integer> list) {
if (root == null) {
list.add(null);
return;
}
list.add(root.val);
addRight(root.right, list);
addRight(root.left, list);
}
}


