题解 | #走方格的方案数# #动态规划# #递归#
走方格的方案数
https://www.nowcoder.com/practice/e2a22f0305eb4f2f9846e7d644dba09b
# 走方格的方案数
n, m = map(int,input().split())
dp = [[1 for _ in range(n+1)] for _ in range(m+1)]
#动态规划的方法
for i in range(1,m+1):
for j in range(1,n+1):
dp[i][j] = dp[i-1][j]+dp[i][j-1]
print(dp[m][n])
# 递归的方法
def func(x,y):
if x < 0 or y < 0:
return 0
elif x == 0 or y == 0:
return 1
else:
return func(x-1, y)+func(x, y-1)
while True:
try:
n, m = map(int, input().split())
res = func(n, m)
print(res)
except:
break

