题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
int main() {
int n=0;
scanf("%d",&n);
int arr[n];
float num=0.0;
for(int i=1;i<=n;i++)
{
scanf("%d",&arr[i]);
if(arr[i]>60)
{
num+=0.2;
}
else
{
num+=0.1;
}
}
printf("%f",num);
return 0;
}
