题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/** * struct ListNode { * int val; * struct ListNode *next; * }; */ class Solution { public: /** * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ ListNode* reverseBetween(ListNode* head, int m, int n) { if (head == nullptr) return nullptr; ListNode* dummy = new ListNode(0); dummy->next = head; cout << dummy->val << endl; // 改变q也能够改变哨兵结点dummy,让头结点一直保持原样 ListNode *q = dummy; for (int i = 0; i < m-1; ++i) { q = q->next; } ListNode *start = q; for (int i = m; i <= n; ++i) { q = q->next; } ListNode *end = q->next; q->next = nullptr; ListNode *p = nullptr; q = start->next; while (q != nullptr) { ListNode *t = q->next; q->next = p; p = q; q = t; } start->next = p; while (p ->next != nullptr) { p = p->next; } p->next = end; return dummy->next; } };