题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
tmp=list(map(int,input().split()))
n,head,deleting=tmp[0],tmp[1],tmp[-1]
cur,pre,l=[],[],[head]
for i in range(2,len(tmp)-1,2):
cur.append(tmp[i])
for i in range(3,len(tmp)-1,2):
pre.append(tmp[i])
for i in range(len(pre)):
l.insert(l.index(pre[i])+1,cur[i])
l.pop(l.index(deleting))
for val in l:
print(val,end=" ")
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