题解 | #Day of Week#

#include<cstdio>
#include<iostream>
#include<string>
#include<map>
using namespace std;
int main()
{
	int year,mon,day;
	char str[1000];
	string month;
	int mday[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
	string inttoweek[7]={"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday"};	
	map<string,int> monthto={
		{	"January",1},
		{"February",2},
	    {"March",3},
	    {"April",4},
		{"May",5},
		{"June",6},
		{"July",7},
		{"August",8},
		{"September",9},
		{"October",10},
		{"November",11},
		{"December", 12}
};
	while(scanf("%d%s%d",&day,str,&year)!=EOF){
		month=str;//将C字符串转换为C++字符串
//		if(month=="January"){
//			mon=1;
//			printf("mon=%d,month=%s",mon,month.c_str());
//		}
//		else if(month=="February")
//		{
//			month=2;
//			printf("mon=%d,month=%s",mon,month.c_str());
//		}
        mon= monthto[month]; 
		bool isBefore;
		if(year<2023||year==2023&&mon<4||year==2023&&mon==4&&day<24)
		{
			isBefore=true;
		}
		else
		isBefore=false;
		
		int beginyear,beginmon,beginday,endyear,endmon,endday;
		if(isBefore){
			beginyear=year;
			beginmon=mon;
			beginday=day;
			endyear=2023;
			endmon=4;
			endday=24;
		}
		else
		{
			beginyear=2023;
			beginmon=4;
			beginday=24;
			endyear=year;
			endmon=mon;
			endday=day;
		}
		int totalday=0;
		while(true){
			if(beginyear==endyear&&beginmon==endmon&&beginday==endday)
			{
				break;
			}
			totalday++;
			//nextday
			bool isLeap=beginyear%400==0||beginyear%4==0&&beginyear%100!=0;
			if(isLeap)
			{
				mday[2]=29;
			}
			else
			mday[2]=28;
			
			++beginday;
			if(beginday>mday[beginmon])
			{
				beginday=1;
				++beginmon;
				if(beginmon>12){
					beginmon=1;
					++beginyear;
				}
			}
		}
		if(isBefore)
		{
		  printf("%s\n",inttoweek[(8-totalday%7)%7].c_str());	
		} 
		 else{
		 
		printf("%s\n",inttoweek[((totalday+1)%7)].c_str());
	}
	}
 } 

//int main()
//{
//	map<string,string> mm = {
//		{"CAIXUKUN","ikun"},
//		{"zhangjie","star"} 
//	}; 
//	char str[100];
//	scanf("%s",str);
//	string name=str;
//	//myMap[key]  根据key映射到对应的值（C++风格的字符串） 
//	printf("%s对应%s",name.c_str(),mm[name].c_str());
//}

还是nextday策略，明白星期的算法