题解 | #人民币转换#

import sys


def num_china(n):
    if n == 1:
        return "壹"
    if n == 2:
        return "贰"
    if n == 3:
        return "叁"
    if n == 4:
        return "肆"
    if n == 5:
        return "伍"
    if n == 6:
        return "陆"
    if n == 7:
        return "柒"
    if n == 8:
        return "捌"
    if n == 9:
        return "玖"
    if 10 <= n < 100:
        if n//10!=1:
            s = f"{num_china(n//10)}拾"
        else:
            s="拾"
        return s+num_china(n%10)
    if 100 <= n < 1000:
        s = f"{num_china(n//100)}佰"
        if 0 < n - (n // 100)*100 < 10:
            s += "零"
        return s+num_china(n%100)
    if 1000 <= n < 10000:
        s = f"{num_china(n//1000)}仟"
        if 0 < n - (n // 1000) *1000< 100:
            s += "零"
        return s+num_china(n%1000)
    if 10000 <= n < 100000000:
        s = f"{num_china(n//10000)}万"
        if 0 < n - (n // 10000)*10000 < 1000:
            s += "零"
        return s+num_china(n%10000)
    if 100000000 <= n:
        s = f"{num_china(n//100000000)}亿"
        if 0 < n - (n // 100000000)*100000000< 1000 or 10000<=n - (n // 100000000)*100000000<=10000000:
            s += "零"
        return s+num_china(n%100000000)


for line in sys.stdin:
    a = line.split()
    n=a[0]
    sum="人民币"
    zhengshu=int(float(n))
    # print(num_china(zhengshu)
    # print(str(num_china(zhengshu)))
    xiaoshu=float(n)-zhengshu
    xiaoshu=0
    try:
        xiaoshu=n.split(".")[1]
    except:
        continue
    if zhengshu:
        sum+=str(num_china(zhengshu))
        sum+="元"
    if xiaoshu:
        # print(xiaoshu)
        tmp_xiaoshu=int(xiaoshu)
        # print(tmp_xiaoshu)
        if tmp_xiaoshu//10:
            sum+=f"{str(num_china(tmp_xiaoshu//10))}角"
        if tmp_xiaoshu%10:
            sum+=f"{str(num_china(tmp_xiaoshu%10))}分"
    else:
        sum+="整"
    print(sum)