题解 | #旋转数组的最小数字#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param rotateArray int整型一维数组 
# @return int整型
#
class Solution:
    def minNumberInRotateArray(self , rotateArray: List[int]) -> int:
        # write code here
        min = rotateArray[len(rotateArray) - 1]
        mid = 0
        left = 0
        right = len(rotateArray) - 1
        while left <= right:
            mid = (left + right) // 2
            if rotateArray[mid] == min:
                right -= 1
                if rotateArray[right] < min:
                    min = rotateArray[right]
            elif rotateArray[mid] > min:
                left = mid + 1
            else:
                min = rotateArray[mid]
                right = mid - 1
        
        return min