题解 | #加起来和为目标值的组合(四)#
加起来和为目标值的组合(四)
https://www.nowcoder.com/practice/7a64b6a6cf2e4e88a0a73af0a967a82b?tpId=117&tqId=39470&rp=1&ru=/exam/oj&qru=/exam/oj&sourceUrl=%2Fexam%2Foj%3Fpage%3D4%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D117&difficulty=undefined&judgeStatus=undefined&tags=&title=
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型vector
* @param target int整型
* @return int整型
*/
int combination(vector<int>& nums, int target) {
// write code here
vector<int> dp(target + 1);
dp[0] = 1;
for (int i = 1; i <= target; ++i) {
for (const auto &num : nums) {
if (i - num >= 0) {
dp[i] += dp[i - num];
}
}
}
return dp[target];
}
};
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