题解 | #矩阵转置#
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
#include <stdio.h>
#define M 10
#define N 10
int main() {
int m = 0;
int n = 0;
while (2 == scanf("%d %d", &n, &m))
{
int arr[N][M] = {0};
// 输入
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
scanf("%d", &arr[i][j]);
}
}
// 输出
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
{
printf("%d ", arr[j][i]);
}
printf("\n");
}
}
return 0;
}
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