题解 | #在字符串中找出连续最长的数字串#

#include<stdio.h>
#include<string.h>
int main()
{
    char str[201];
    int i, j, max, index = 0; 
    while(scanf("%s", str) != EOF)
    {
        i = 0;
        max = 0;
        while((i < strlen(str)) && (str[i] != '\n'))//i遍历字符串
        {
            if(str[i] >= '0' && str[i] <= '9')//找到数字串的起始点
            {
                j = i;
                while((i < strlen(str)) && (str[i] >= '0') && (str[i] <= '9'))//求数字串的长度
                    i++;
                if(i - j > max)//若长度长于已记录的最长长度，将数字串写入覆盖原来的字符串
                {
                    max = i - j;
                    index = 0;
                    while(j < i)
                        str[index++] = str[j++];
                }
                else
                    if(i - j == max)//若长度和已记录的最长长度相同，将数字串续写入原来的字符串
                    {
                        while(j < i)
                            str[index++] = str[j++];
                    }
            }
            i++;
        }
        for(i = 0; i < index; i++)
            printf("%c", str[i]);
        printf(",%d\n", max);
    }
}