题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include<cstdio>
long long fun(int n){
if(n == 1){
return 1;
}else {
return n * fun(n-1);
}
}
int main(){
int n;
while(scanf("%d",&n) != EOF){
printf("%lld\n",fun(n));
}
}
