题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
#include <iostream>
#include <string>
using namespace std;
// 依据规则对改变每个字符
int main() {
string str1, str2;
getline(cin, str1);
getline(cin, str2);
for (int i = 0; i < str1.size(); ++i) {
if (str1[i] <= 'z' && str1[i] >= 'a') {
if (str1[i] == 'z')
str1[i] = 'A';
else
str1[i] -= 31;
} else if (str1[i] <= 'Z' && str1[i] >= 'A') {
if (str1[i] == 'Z')
str1[i] = 'a';
else
str1[i] += 33;
} else {
if (str1[i] == '9')
str1[i] = '0';
else
str1[i]++;
}
}
for (int i = 0; i < str2.size(); ++i) {
if (str2[i] <= 'z' && str2[i] >= 'a') {
if (str2[i] == 'a')
str2[i] = 'Z';
else
str2[i] -= 33;
} else if (str2[i] <= 'Z' && str2[i] >= 'A') {
if (str2[i] == 'A')
str2[i] = 'z';
else
str2[i] += 31;
} else {
if (str2[i] == '0')
str2[i] = '9';
else
str2[i]--;
}
}
cout << str1<<endl;
cout << str2<<endl;
}
// 64 位输出请用 printf("%lld")
#include <iostream>
#include <string>
using namespace std;
// 字典法
// 列出解密/加密符号的对应值
int main() {
string a = "zabcdefghijklmnopqrstuvwxyZABCDEFGHIJKLMNOPQRSTUVWXY9012345678";
string b = "bcdefghijklmnopqrstuvwxyzaBCDEFGHIJKLMNOPQRSTUVWXYZA1234567890";
string str1, str2;
getline(cin, str1);
getline(cin, str2);
for (int i = 0; i < str1.size(); ++i) {
char ch = str1[i];
if (ch >= 'A' && ch <= 'Z')
str1[i] = b[ch - 'A'];
else if (ch >= 'a' && ch <= 'z')
str1[i] = b[ch - 'a' + 26];
else
str1[i] = b[ch - '0' + 52];
}
for (int j = 0; j < str2.size(); ++j) {
char ch = str2[j];
if (ch >= 'A' && ch <= 'Z')
str2[j] = a[ch - 'A'];
else if (ch >= 'a' && ch <= 'z')
str2[j] = a[ch - 'a' + 26];
else
str2[j] = a[ch - '0' + 52];
}
cout << str1 << endl;
cout << str2 << endl;
}
// 64 位输出请用 printf("%lld")
