题解 | #数字之和#

#include <iostream>
#include <string>

using namespace std;
int posSum(int n) {
    string str = to_string(n);
    int sum = 0;
    for (int i = 0; i < str.size(); ++i) {
        sum += str[i] - '0';
    }
    return sum;
}
int powerSum(int n) {
    string str = to_string(n * n);
    int sum = 0;
    for (int i = 0; i < str.size(); ++i) {
        sum += str[i] - '0';
    }
    return sum;
}
int main() {
    int n;
    while (cin >> n) {
        cout << posSum(n) << " " << powerSum(n) << endl;
    }
}