题解 | #学英语#

import sys
#三位一组划分,比如1,652,510会变成列表[1,652,510]
n = list(input())[::-1]
n_new = []
num = 0
for i in n:
    if num%3 == 0 and num!=0:
        n_new.append('.')
    n_new.append(i)
    num += 1
n_new =''.join(n_new[::-1]).split('.')

list_1 = [0,'one','two','three','four',
        'five','six','seven','eight','nine',
        'ten','eleven','twelve','thirteen',
        'fourteen','fifteen','sixteen','seventeen',
        'eighteen','nineteen']

list_2 = [0,0,'twenty','thirty','forty','fifty','sixty','seventy','eighty','ninety']

#1000以内
def l_1000(nums,connect=''):
    #如果是1,088这种就去掉88前面的'and'拼接
    if nums < 100:
        connect = ''
    result=''
    if 0< nums < 20:
        result = connect+list_1[int(nums)]
    elif 20 <= nums < 100:
        if nums % 10 ==0:
            result += connect+list_2[nums//10]
        else:
            result += connect+list_2[nums//10] + ' ' + list_1[nums%10]
    elif 100 <= nums <1000:
        if nums % 100 == 0:
            result += list_1[nums//100] + ' hundred'
        else:
            result += list_1[nums//100] + ' hundred and ' + l_1000(nums%100)
    return result
#1000,000
def l_10w(nums):
    return l_1000(nums) + ' thousand '

#1,000,000
def l_100w(nums):
    return l_1000(nums) + ' million '
    
if len(n_new) == 1:
    print(l_1000(int(n_new[0])))
if len(n_new) == 2:
    print(l_10w(int(n_new[0]))+l_1000(int(n_new[1]),connect='and '))
if len(n_new) == 3:
    print(l_100w(int(n_new[0]))+l_10w(int(n_new[1]))+l_1000(int(n_new[2]),connect='and '))