题解 | #连续子数组的最大乘积#

连续子数组的最大乘积

https://www.nowcoder.com/practice/fd8c819c07c9493887bfac8549c119f4

#include <bits/stdc++.h>
using namespace std;

int main() {
   int n;
   cin >> n;
   vector<int> arr(n);
   for(int i = 0; i < n; i++) cin >> arr[i];
   vector<int> mx(n,0),mn(n,0);
   mn[0] = mx[0] = arr[0];
   int ret = arr[0];

   for(int i = 1; i < n; i++) {
    if(arr[i] == 0){
        mx[i] = 0;
        mn[i] = 0;
    }else if(arr[i] > 0){
        mx[i] = max(arr[i]*mx[i-1],arr[i]);
        mn[i] = min(arr[i],arr[i]*mn[i-1]);
    }else {
        mx[i] = max(arr[i] * mn[i-1],arr[i]);
        mn[i] = min(arr[i],mx[i-1]*arr[i]);
    }
    
    if(mx[i] > ret) ret = mx[i];
   }
   cout << ret << endl;
   return 0;
}
// 64 位输出请用 printf("%lld")

全部评论

相关推荐

点赞 收藏 评论
分享
牛客网
牛客企业服务