题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
s = list(map(int,input().split())) li = s[2:-1] end = s[-1] lis = [s[1]] for i in range(0,len(li),2): a = lis.index(li[i+1]) lis.insert(a+1,li[i]) lis.remove(end) print(*lis)