题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
s = list(map(int,input().split()))
li = s[2:-1]
end = s[-1]
lis = [s[1]]
for i in range(0,len(li),2):
a = lis.index(li[i+1])
lis.insert(a+1,li[i])
lis.remove(end)
print(*lis)
