题解 | #序列重组矩阵#
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
n,m = map(int,input().split(" "))
num = list(input().split(" "))
for i in range(n):
print(" ".join(str(i) for i in num[m*i:m*(i+1)]))
序列重组矩阵
https://www.nowcoder.com/practice/7548f8f5e44c42fa84fb2323d899a966
n,m = map(int,input().split(" "))
num = list(input().split(" "))
for i in range(n):
print(" ".join(str(i) for i in num[m*i:m*(i+1)]))
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