题解 | #表示数字#

#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main() {
    char str[100] = {0};
    char str1[200] = {0};
    while (scanf("%s", str) != EOF) { // 注意 while 处理多个 case
       int len = strlen(str);
       int i = 0,k = 0;
       for(i=0, k=0; i<len; i++,k++)
       {
            //if((str[i] >= '0' && str[i] <= '9' ) && (str[i-1] < '0' && str[i-1] >'9') )//为什么这样判断不了？
            if((!isdigit(str[i-1])) && isdigit(str[i]) )
            {
                str1[k++] = '*';
                //k++;
                str1[k] = str[i];

            }
            else if(!isdigit(str[i]) && isdigit(str[i-1]) )
            {
                str1[k++] = '*';
                //k++;
                str1[k] = str[i];
            }
            else {
                str1[k] = str[i];
            }
       }
       if(isdigit(str[len-1]))
        {
            strcat(str1,"*");
        }
        for(int j = 0; j<strlen(str1); j++)
        {
            printf("%c",str1[j]);
        }
        printf("\n");
    }
    return 0;
}