题解 | #字符串的反码#

#include <iostream>
using namespace std;
#include <string>

int main() {
    string str;
    string  ch;
    int len = 0;    //距离
    while (cin >> str) { // 注意 while 处理多个 case
       for (int i = 0; i < str.size(); i++){
        if (str[i] >= 'a' && str[i] <= 'z'){ //小写
            len = str[i] - 'a';
           // cout<<len<<endl;
           ch = 'z'-len;
           cout<<ch;
        }
        else if(str[i] >= 'A' && str[i] <= 'Z'){//大写
            len = str[i] - 'A';
           // cout<<len<<endl;
            ch = 'Z'-len;
            cout<<ch;
        }
        else {//不在英文字母范围内，则直接输出
         cout<<str[i];
        }
       }
    }
}