题解 | #单链表的排序#

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 * }
 */

public class Solution {
    /**
     * 
     * @param head ListNode类 the head node
     * @return ListNode类
     */
    public ListNode sortInList (ListNode head) {
        // write code here
        ListNode pre=head;
        ListNode list=new ListNode(-1);
        ArrayList<Integer> arrayList=new ArrayList<Integer>();
        while(pre!=null){
            arrayList.add(pre.val);
            pre=pre.next;
        }
        arrayList.sort(Comparator.naturalOrder());
        ListNode back=head;
        for(int i=0;i<arrayList.size();i++){
            back.val=arrayList.get(i);
            back=back.next;
        }
        return head;
    }
}