题解 | #简单密码#

#include <iostream>
using namespace std;


char change(char c){
    if(c>='a'&&c<='c')return '2';
    if(c>='d'&&c<='f')return '3';
    if(c>='g'&&c<='i')return '4';
    if(c>='j'&&c<='l')return '5';
    if(c>='m'&&c<='o')return '6';
    if(c>='p'&&c<='s')return '7';
    if(c>='t'&&c<='v')return '8';
    if(c>='w'&&c<='z')return '9';
    if(c>='A'&&c<='Y')return c+32+1;
    if(c=='Z')return 'a';
    return c;
}
int main() {
    char c;
    while (cin>>c) { // 注意 while 处理多个 case
        cout<<change(c);

    }
}
// 64 位输出请用 printf("%lld")